It is given that the curve $C$ has equation \(y = \dfrac{(2x-1)(1-x)}{x},\ x\in \mathbb{R},\ x\ne

Question

It is given that the curve $C$ has equation $y = \dfrac{(2x-1)(1-x)}{x},\ x\in \mathbb{R},\ x\ne 0.$ Use an algebraic method to find exactly the set of values that $y$ can take.

Accepted Answer

$y \leq 3 - 2\sqrt 2$ or $y \geq 3 + 2\sqrt 2$

Worked Example 1

Worked Example 1

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