The curve $C$ has equation $\frac{(y-3)^2}{5}-\frac{(x+2)^2}{9}=1$. Sketch $C$, stating the eq

Question

The curve $C$ has equation $\frac{(y-3)^2}{5}-\frac{(x+2)^2}{9}=1$. Sketch $C$, stating the equations of the asymptotes and their point of intersection.[3] Hence state the exact range of values of $m$ such that the straight line $y=m(x+2)+3$ intersect $C$.[2]

Accepted Answer

(ii) $m>\frac{\sqrt{5}}{3}$or $m<-\frac{\sqrt{5}}{3}$

Graphing Techniques

Graphing Techniques