In the diagram, $PQRS$ is a straight line. Given that $PU$ is parallel to $QT$, \(\angle

Question

In the diagram, $PQRS$ is a straight line. Given that $PU$ is parallel to $QT$, $\angle TRS=108{}^\circ $, $\angle UPR=(k-8){}^\circ \mathrm{ and }\angle QTR=k{}^\circ $. Find the value of $k$, $\angle UPR$.

Accepted Answer

(a) $k = 58$ (b) $50°$

Geometry: Solving for \(k\) Using Parallel Lines

Geometry: Solving for \(k\) Using Parallel Lines

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