The diagram shows two triangles $ABE$ and $ACD$, where $AB = 3.5\text{ cm}$, \(BC = 2.1\t

Question

The diagram shows two triangles $ABE$ and $ACD$, where $AB = 3.5\text{ cm}$, $BC = 2.1\text{ cm}$, $AE = 3\text{ cm}$ and $DE = 1.8\text{ cm}$. Without assuming that $BE$ is parallel to $CD$, show that the triangle $ABE$ is similar to triangle $ACD$, stating your reasons clearly. Find the length $BE$, given that the length $CD$ is $8.4\text{ cm}$.

Accepted Answer

$\text{(i)}\ \triangle ABE\sim\triangle ACD\text{ (SAS)}$ $\text{(ii)}\ 5.25\text{ cm}$

Geometric Similarity and Proportionality in Nested Triangles

Geometric Similarity and Proportionality in Nested Triangles

Video Solution:

Solution:

Solution locked