Given that the $n^{th}$ term, $T_n$, of a sequence is $T_n = n^2 + 1$. Write down the first \(

Question

Given that the $n^{th}$ term, $T_n$, of a sequence is $T_n = n^2 + 1$. Write down the first $5$ terms of the sequence. Find the lowest common multiple of the $7^{th}$ and the $8^{th}$ term. Find the highest common factor of the $4^{th}$ and the $13^{th}$ term. The first $5$ terms of another sequence are $4, 7, 12, 19, 28$. By comparing this sequence and the sequence in (i), find a formula for the $n^{th}$ term of this sequence in terms of $n$. Hence find the $21^{st}$ term of this sequence.

Accepted Answer

(i)(a) $2,5,10,17,26$ (i)(b) LCM $=650$ (i)(c) HCF $=17$ (ii)(a) $T_n=n^2+3$ (ii)(b) $444$

General Term of a Sequence

General Term of a Sequence

Video Solution:

Solution:

Solution locked