It is given that $P$ is a point on the circumference of circle $C: x^2 + y^2 = r^2$ and \(A

Question

It is given that $P$ is a point on the circumference of circle $C: x^2 + y^2 = r^2$ and $AB$ is the diameter on the $x$-axis. Using an algebraic method, show that $\angle APB = 90^\circ$, i.e., angle in a semicircle is always equal to $90^\circ$.

Accepted Answer

$\angle APB=90^\circ$, for $P\ne A,B$.

Coordinate Geometry - Parallel and Perpendicular Lines

Coordinate Geometry - Parallel and Perpendicular Lines

Solution:

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