Sketch the curve with equation \(y=\left|\frac{4}{p-x}\right|\), where \(p\) is a positive constant. State, in terms of \(p\), the equations of the asymptotes and the coordinates of any intersections with the coordinate axes. On the same diagram, sketch the line with equation \(y=q(x-p)\), where \(q\) is a positive constant.[4]
Find, in terms of \(p\) and \(q\), the root of the equation \(\left|\frac{4}{p-x}\right|=q(x-p)\).[3]
Hence solve the inequality \(\left|\frac{4}{p-x}\right|>q(x-p)\).[2]
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Answer:(i) Asymptotes \(x=p\) and \(y=0\), \(y\)-intercept \(\left(0,\frac4p\right)\), no \(x\)-intercept (ii) \(x=p+\frac2{\sqrt q}\) (iii) \(x<p\) or \(p<x<p+\frac2{\sqrt q}\)