It is given that
\[\mathrm{f}(x) = \left\{ \begin{array}{ll} 4-2x & \text{for}\hspace{0.5em} 0 < x \le 2 \\ -(x - 4)^2 + 4 & \text{for}\hspace{0.5em} 2 < x \le 4 \end{array} \right.\]
and \(\mathrm{f}(x) = \mathrm{f}(x + 4)\) for all real values of \(x\).


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