Train journey with a speed limit

Train journey with a speed limit

IP 3
9 marks

A train leaves a station from rest and accelerates uniformly at \(0.5\) m/s\(^2\) to a cruising speed of \(V\) m/s. It travels at this speed and then decelerates uniformly at \(1\) m/s\(^2\), coming to rest at the next station. Model the train as moving along a straight track.

  1. Using a speed–time graph, show that if the whole journey takes \(150\) s, the distance travelled is \((150V-1.5V^2)\) m.[3]
  2. The stations are \(2\) km apart and the journey takes \(150\) s. Find \(V\), explaining why one solution of your equation must be rejected.[3]
  3. The speed limit on the track is \(20\) m/s. With the same acceleration and deceleration, find the shortest possible time for the \(2\) km journey, justifying that it is the shortest.[3]

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Answer:(b) \(V=50-\dfrac{10\sqrt{105}}{3}\approx 15.8\) m/s (c) \(130\) s

Need help? Join our IP Math tuition programme.

Learn more