Solve \(2x^2+3x-4=0\) using the quadratic formula. Give answers to \(3\) s.f. State the number of \(x\)-intercepts of \(y=2x^2+3x-4\).[4]
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Answer:\(\frac{-3\pm\sqrt{41}}{4}\). To \(3\) significant figures, \(x=0.851\) or \(x=-2.35\). Since there are two real roots, the graph has \(2\) \(x\)-intercepts.