A ball is thrown upwards. Its height after $t$ seconds is $h=-5t^2+20t+1$. Find its initial heig

Question

A ball is thrown upwards. Its height after $t$ seconds is $h=-5t^2+20t+1$. Find its initial height, the time and height at its maximum, and when it hits the ground (positive time, to $2$ d.p.).[6]

Accepted Answer

Initial height $1\text{ m}$; Maximum height $21\text{ m}$ at $2\text{ s}$; Hits the ground after $4.05\text{ s}$.

Functions and Graphs

Functions and Graphs

Solution:

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