\(z\) varies directly as \(x\) and inversely as \(y^2\). When \(x=6\) and \(y=2\), \(z=15\). Find
\(z\) in terms of \(x\) and \(y\);
\(z\) when \(x=4\) and \(y=3\);
\(x\) when \(z=10\) and \(y=3\).
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