$z$ varies directly as $x$ and inversely as $y^2$. When $x=6$ and $y=2$, \(

Question

$z$ varies directly as $x$ and inversely as $y^2$. When $x=6$ and $y=2$, $z=15$. Find $z$ in terms of $x$ and $y$; $z$ when $x=4$ and $y=3$; $x$ when $z=10$ and $y=3$.

Accepted Answer

(a) $z=\frac{10x}{y^2}$; (b) $z=\frac{40}{9}$; (c) $x=9$.

Functions and Graphs

Functions and Graphs

Solution:

Solution locked