For $y=−2(x+1)^2+8$, state the vertex, axis of symmetry, direction of opening and $y$-inter

Question

For $y=−2(x+1)^2+8$, state the vertex, axis of symmetry, direction of opening and $y$-intercept. Sketch the graph, labelling its vertex and intercepts.[5]

Accepted Answer

Vertex $(−1,8)$; Axis $x=−1$; opens down; $y$-intercept $(0,6)$; Roots $(−3,0),(1,0)$.

Functions and Graphs

Functions and Graphs

Solution:

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