Given the original graphs, $y=\mathrm{f}\left( x \right)$, sketch the reciprocal graph, \(y=\frac{

Question

Given the original graphs, $y=\mathrm{f}\left( x \right)$, sketch the reciprocal graph, $y=\frac{1}{\mathrm{f}\left( x \right)}$, respectively. $y=\text{f}\left( x \right)$ $y=\frac{1}{\text{f}\left( x \right)}$

Accepted Answer

Four reciprocal sketches shown. (1) Asymptotes $x=0,y=0$. (2) Vertical asymptotes $x=-3,1$, maximum $\left(-1,-\frac25\right)$, intercept $\left(0,-\frac12\right)$. (3) Vertical asymptotes $x=-5,-1,2$, minimum $\left(-3,\frac12\right)$, maximum $(0,-1)$. (4) Vertical asymptotes $x=0,4$, maximum $\left(2,-\frac13\right)$, left horizontal asymptote $y=-\frac23$.

Transformations of Graphs - Reciprocal Graph, \(y=\frac{1}{f(x)}\)

Transformations of Graphs - Reciprocal Graph, \(y=\frac{1}{f(x)}\)

Solution:

Solution locked

\(y=\text{f}\hspace{0.1em}\left( x \right)\)	\(y=\frac{1}{\text{f}\hspace{0.1em}\left( x \right)}\)