Forming Equations with Transformed Roots

Forming Equations with Transformed Roots

IB Year 6 | Grade 12
New roots, new equation

A common task gives a quadratic with roots \(\alpha\) and \(\beta\), then asks for a new equation whose roots are a transformation of them — such as \(2\alpha\) and \(2\beta\), or \(\alpha^2\) and \(\beta^2\). You never need the roots themselves: find the new sum and the new product, then write \(x^2-(\text{new sum})\,x+(\text{new product})=0\).

The three-step method

  1. Find \(\alpha+\beta\) and \(\alpha\beta\) from the given equation.
  2. Express the new sum and new product in terms of \(\alpha+\beta\) and \(\alpha\beta\), and evaluate them.
  3. Substitute into \(x^2-(\text{new sum})\,x+(\text{new product})=0\) and clear any fractions.

Common transformations

New rootsNew sumNew product
\(k\alpha,\ k\beta\)\(k(\alpha+\beta)\)\(k^2\alpha\beta\)
\(\alpha+k,\ \beta+k\)\((\alpha+\beta)+2k\)\(\alpha\beta+k(\alpha+\beta)+k^2\)
\(\dfrac{1}{\alpha},\ \dfrac{1}{\beta}\)\(\dfrac{\alpha+\beta}{\alpha\beta}\)\(\dfrac{1}{\alpha\beta}\)
\(\alpha^2,\ \beta^2\)\((\alpha+\beta)^2-2\alpha\beta\)\((\alpha\beta)^2\)
\(\alpha^3,\ \beta^3\)\((\alpha+\beta)^3-3\alpha\beta(\alpha+\beta)\)\((\alpha\beta)^3\)
Exam check

Finish with integer coefficients: multiply through to clear fractions, and remember the "\(=0\)" — an equation, not an expression, is asked for.

The reciprocal-root identities and the displayed ratios require both roots to be nonzero, so \(\alpha\beta\ne0\). Check this condition before using those identities or forming an equation with reciprocal roots.

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