$ABCD$ is a parallelogram and $\Delta BCE$ is an isosceles triangle. Given that \(\angle BE

Question

$ABCD$ is a parallelogram and $\Delta BCE$ is an isosceles triangle. Given that $\angle BEC=55{}^\circ $ and $\angle ADB=50{}^\circ $, find $\angle CBE$, $\angle ABD$, stating your reason(s) clearly.

Accepted Answer

(a) $\angle CBE=70^\circ$ (b) $\angle ABD=60^\circ$

Finding Unknown Angles Using Parallelogram and Isosceles Triangle Properties

Finding Unknown Angles Using Parallelogram and Isosceles Triangle Properties

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