Let \(f(x)=60\mathrm{e}^{-\frac{x}{3}}\), \(x\in\mathbb{R}^+\). The line \(y=x\) intersects the curve \(y=f(x)\) at \(P\).
The straight line \(L\), with gradient \(-1\), is a tangent to the curve \(y=f(x)\) at \(Q\).
The region \(R\), shaded in the diagram, is bounded by the graph of \(f\), the line \(y=x\) and the line \(L\).
In addition, \(L\) is a tangent to the curve \(y=f^{-1}(x)\), where \(f^{-1}\) is the inverse function of \(f\), as shown in the second diagram.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more