Simplify \(2^{3x - 4} \times 9^{x - 3} = 6^{2(x - 2)}\) in the form \(\left(\frac{m \times n}{36}\right)^x = 9\), where \(m\) and \(n\) are integers.
Hence solve for \(x\), giving your answer in the simplest form \(\frac{\ln a}{\ln b}\), where \(a\) and \(b\) are integers.[5]
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