Solving Exponential Equations

Solving Exponential Equations

Secondary 3
TGM Original Questions

For \(a>0\) and \(a\ne1\):

\(a^u=a^v\quad\Longleftrightarrow\quad u=v\)

Methods

FormMethodExample
Powers of the same baseEquate indices.\(2^{3x-1}=8\Rightarrow3x-1=3\Rightarrow x=\frac43\)
Quadratic in \(a^x\)Let \(u=a^x>0\).Solve for u, reject non-positive values, then find x.

Useful substitutions

EquationSubstitutionBecause
\(9^x-4(3^x)+3=0\)
\(\mathrm{e}^{2x}-7\mathrm{e}^{x}+10=0\)
\(\mathrm{e}^{4x}-3\mathrm{e}^{2x}-4=0\)
\(25^x=4-3(25^{-x})\)

Factor out shifted powers first, e.g. \(2^{x+1}=2(2^x)\).

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