2025 NOV TZ1 P1 Q5

Given that \(x > 7\), show that \(\frac{x}{x^2 - 8x + 7} \times \frac{x^2 - 1}{x + 1} = \frac{x}{x - 7}\).

Hence, or otherwise, solve \(\log_{2}{[x(x^2 - 1)]} - 1 = \log_{2}{[(x^2 - 8x + 7)(x + 1)]}\).