The roots of the equation $x^3-5x^2+2x+8=0$ are $\alpha$, $\beta$ and $\gamma$. Find the val

Question

The roots of the equation $x^3-5x^2+2x+8=0$ are $\alpha$, $\beta$ and $\gamma$. Find the value of $\alpha^2+\beta^2+\gamma^2$. By considering the factorised form of $x^3-5x^2+2x+8$, find the value of $(1-\alpha)(1-\beta)(1-\gamma)$.

Accepted Answer

(a) $21$ (b) $6$

Evaluating expressions in the roots of a cubic

Evaluating expressions in the roots of a cubic

Solution:

Solution locked