Use the constraint to express the quantity to optimise in one variable. State the feasible domain.
\(V^{\prime}(x)=0\)
Find the interior stationary points and test their nature. Compare admissible endpoints and relevant limits for a global maximum or minimum.
Discard infeasible values. An excluded endpoint may give a limiting value that is never attained.
Mensuration formulae
| Solid | Volume | Curved surface area |
|---|---|---|
| Cylinder | ||
| Cone | ||
| Sphere |
Substitute back to find the requested quantity and include units. Add bases when total surface area is required.
Example
A rectangle has perimeter \(20\) cm and width \(x\) cm, so its area is \(A=x(10-x)\) with \(0<x<10\).
\(\dfrac{\mathrm dA}{\mathrm dx}=10-2x=0\Rightarrow x=5;\qquad \dfrac{\mathrm d^2A}{\mathrm dx^2}=-2<0\), so the greatest area is \(5\times5=25\text{ cm}^2\).
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