Find the equation of the tangent and the normal to the curve $y=x^3+x^2-4x-3$ at the point where \

Question

Find the equation of the tangent and the normal to the curve $y=x^3+x^2-4x-3$ at the point where $x=-2$.

Accepted Answer

Tangent: $y=4x+9$ Normal: $y=-\frac14x+\frac12$

Equations of Tangents and Normals to Curve