For a nonvertical line, \(y=mx+c\): \(m\) is its gradient and \(c\) is its y-intercept. Every point on the line satisfies its equation.
Given a point \((x_1,y_1)\) and gradient \(m\), substitute into \(y=mx+c\) to find \(c\). If two points are given, find the gradient first.
| Feature | How to find it |
|---|---|
| x-intercept | Set \(y=0\). |
| y-intercept | Set \(x=0\). |
| Vertical line through a point | Its equation is \(x=\text{the point’s x-coordinate}\). |
Two distinct points determine a straight line. Plot a third point as a check. The intersection of two lines satisfies both equations; check a graphical reading by substitution.
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