Equal distances from an angle bisector

Equal distances from an angle bisector

Secondary 4
5 marks
TGM Original Questions

In the diagram, \(AP\) bisects \(\angle MAN\). The perpendiculars from \(P\) to \(AM\) and \(AN\) meet them at \(M\) and \(N\). Also \(AP=13\) cm and \(AM=12\) cm.

  1. Prove that \(PM=PN\).[3]
  2. Find \(PN\).[2]

Solution:

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Answer:(a) \(PM=PN\) by AAS congruence. (b) \(5\) cm.

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