[EPQ Vol 1A] Question 4

[EPQ Vol 1A] Question 4

Secondary 1

Written as the product of their prime factors,

First integer:
\(2^{p}\times 3^{2}\times 7\)

Second integer:
\(2\times 3^{q}\times 5^{r}\)

The highest common factor of these two integers is \(6\).
The lowest common multiple of these two integers is \(2^{2}\times 3^{2}\times 5^{3}\times 7\).

Find the values of \(p\), \(q\) and \(r\).

Solution:

Solution locked

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Answer:\(p=2,\ q=1,\ r=3\).

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