A right circular cylinder has circular cross-sectional area \(\pi r^2\). Unrolling its curved surface forms a rectangle with width \(2\pi r\) and height \(h\).
| Measure | Formula |
|---|---|
| Volume | \(\pi r^2h\) |
| Curved surface area | \(2\pi rh\) |
| Closed total surface area | \(2\pi rh+2\pi r^2\) |
Example
A closed cylinder has radius 3 cm and height 8 cm. Its volume is \(72\pi\text{ cm}^3\). Its curved area is \(48\pi\text{ cm}^2\) and total surface area is \(66\pi\text{ cm}^2\). With one end open, the area becomes \(57\pi\text{ cm}^2\).
A cylinder is not a polygonal prism, although the same “cross-sectional area × height” volume idea applies. Halve a given diameter before substituting for \(r\).
Create a free account to practise similar questions.
Need help? Join our E-Maths tuition for O-Level success.
Learn more