Look for a part repeated once per position and any fixed extra part. In a row of joined squares, the first square uses four sticks. Each new square shares a side and needs only three new sticks.
Example
\(\begin{aligned}T_n&=4+3(n-1)\\&=3n+1\end{aligned}\)
A row of \(12\) squares needs \(3(12)+1=37\) sticks. Counting four sticks per square would count shared sides twice.
The same expression can be seen as \(n\) top sticks, \(n\) bottom sticks and \(n+1\) vertical sticks. Both counts give \(3n+1\).
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