Expanding \(\dfrac{(x-a)^2}{p^2}+\dfrac{(y-b)^2}{q^2}=1\) gives \(dx^2+ey^2+fx+gy+h=0\). Completing the square reverses the conversion.
\(q>p\)
\(q<p\)
Both forms describe an ellipse with centre \((a,b)\).
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