ABCD is a horizontal rectangular court with $AB=18$ m and $BC=24$ m. A vertical mast CT is 7.5 m

Question

ABCD is a horizontal rectangular court with $AB=18$ m and $BC=24$ m. A vertical mast CT is 7.5 m high. An observer's eye E is vertically 1.5 m above A. The dashed line is horizontal and meets CT at the same height as E. The diagram is not to scale. Find AC.[2] Calculate the angle of elevation $\alpha$ of T from E.[2]

Accepted Answer

(a) $30\text{ m}$ (b) $11.3^\circ$

Elevation from above a court

Elevation from above a court

Solution:

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