Factorial, logarithmic and trigonometric telescoping
Factorial, logarithmic and trigonometric telescoping
6 marks
Tim Gan Math Original
Show that \(\sum_{r=0}^{n-1}\sin((2r+1)\theta)=\frac{\sin^2(n\theta)}{\sin\theta}\), where \(\sin\theta\ne0\).[6]
Solution:
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Answer:\(\frac{\sin^2(n\theta)}{\sin\theta}\)
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