If \(a{{x}^{2}}+bx+c=0\) , where where \(a,b\) and \(c\) are real numbers and \(a\ne 0\), then the solutions are given by
\(x=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\)
This formula for solving quadratic equations is usually used when the quadratic expression cannot be factorised easily.
Tip:
Always express the quadratic equation in the general form \(a{{x}^{2}}+bx+c=0\) so that the correct value for \(a,b\) and \(c\) can be substituted into the formula.
Video solution locked
A free account saves your progress; this video needs tuition enrolment.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.
Create a free account to practise similar questions.
Need help? Join our IP Math tuition programme.
Learn more