Discrete Data Case 1: Number of Data is ODD. NOTE: Always arrange the data in ascending order. Media

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Discrete Data Case 1: Number of Data is ODD. NOTE: Always arrange the data in ascending order. Median will divide the data into $2$ equal halves. Median $= 5$ Lower Quartile, $Q_1 = \frac{2+2}{2} = 2$ Upper Quartile, $Q_3 = \frac{6+9}{2} = 7.5$ Interquartile Range $= Q_3 - Q_1$ $\qquad\qquad\qquad\qquad\;\;\;\,$ $= 7.5 - 2$ $\qquad\qquad\qquad\qquad\;\;\;\,$ $= 5.5$ Range $= \text{Max} - \text{Min}$ $\qquad\qquad\qquad\qquad\;\;\;\,$ $= 11 - 1$ $\qquad\qquad\qquad\qquad\;\;\;\,$ $= 10$ Case 2: Number of data is EVEN. NOTE: Always arrange the data in ascending order. Median will divide the data into $2$ equal halves. Median $= \frac{(5+6)}{2} = 5.5$ Lower Quartile, $Q_1 = 2$ Upper Quartile, $Q_3 = 9$ Interquartile Range $= Q_3 - Q_1$ $\qquad\qquad\qquad\qquad\;\;\;\,$ $= 9 - 2$ $\qquad\qquad\qquad\qquad\;\;\;\,$ $= 7$ Range $= \mathrm{Max} - \mathrm{Min}$ $\qquad\;\;\;\;\;\;\;$ $= 13 - 1$ $\qquad\;\;\;\;\;\;\;$ $= 12$

Accepted Answer

Odd data set: median $5$, $Q_1=2$, $Q_3=7.5$, interquartile range $5.5$, range $10$. Even data set: median $5.5$, $Q_1=2$, $Q_3=9$, interquartile range $7$, range $12$.

Median, Quartiles, Range and Interquartile Range

Median, Quartiles, Range and Interquartile Range

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