Distance with velocity always negative
Distance with velocity always negative
5 marks
TGM Original
A particle has velocity v=-t2-1 m,s-1 for 0 <= t 2 seconds. Find its displacement change and total distance, explaining the sign difference.
Solution:
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Answer:Displacement change \(-\dfrac{14}{3}\) m; distance \(\dfrac{14}{3}\) m. Motion is always in the negative direction, while distance is nonnegative.
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