Distance from a position parabola
Distance from a position parabola
7 marks
TGM Original
A particle has displacement s=6t-t2 metres for 0 <= t 6 seconds. Sketch its velocity–time, acceleration–time and distance–time graphs, labelling endpoint values and the rest time. Distance is measured from t=0.
Solution:
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Answer:\(v=6-2t\ \mathrm{m\,s^{-1}}\), \(a=-2\ \mathrm{m\,s^{-2}}\); rest at \(3\) s. Distance is \(6t-t^2\) m up to \(3\) s and \(t^2-6t+18\) m thereafter, ending at \(18\) m.
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