Direct and Inverse Proportion

Direct and Inverse Proportion

IP 2

Two identical lamps are \(12\) m apart. A sensor lies on the straight line between them, \(x\) metres from Lamp \(A\).

Diagram not drawn to scale.

Each lamp produces \(80\) lux at a distance of \(3\) m. Each obeys an inverse-square model, and their illuminations add.

  1. Form an expression for total illumination at the sensor.

  2. Calculate the total illumination when \(x=3\) and when \(x=6\).

  3. Explain why doubling the sensor’s distance from Lamp \(A\) from \(3\) m to \(6\) m does not divide the total illumination by \(4\).

  4. Find another sensor position with the same total illumination as at \(x=3\), without solving a polynomial equation.

Solution:

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Answer:(a) \(\frac{720}{x^2}+\frac{720}{(12-x)^2}\), \(0<x<12\); (b) \(88\frac89\) lux and \(40\) lux; (c) Second contribution rises; (d) \(x=9\).

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