Given $$y=\frac{6x^3-4x^2+2}{x},\qquad x\ne0,$$ rewrite $y$ as a sum of powers of $x$, then find

Question

Given $$y=\frac{6x^3-4x^2+2}{x},\qquad x\ne0,$$ rewrite $y$ as a sum of powers of $x$, then find $\frac{\mathrm{d}y}{\mathrm{d}x}$.

Accepted Answer

$y=6x^2-4x+2x^{-1}$; $y'=12x-4-\frac2{x^2}$.

Differentiation