Differentiation

Differentiation

Secondary 4

The curve \(y=kx^3\) has gradient \(24\) at \(x=2\).

  1. Find \(k\).

  2. Find the height of the curve at \(x=2\).

  3. Find its gradient at \(x=-1\).

Solution:

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Answer:(a) \(k=2\); (b) Height \(16\); (c) Gradient at \(x=-1\) is \(6\).

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