Differentiation

Differentiation

Secondary 4

For \(y=x^2+1\), a student wants the gradient at \(x=3\).
The student writes: \[y=3^2+1=10, \qquad \frac{\mathrm{d}y}{\mathrm{d}x}=0 \quad\text{because \(10\) is constant.}\]

  1. Explain the error.

  2. Find the correct gradient at \(x=3\).

  3. Find the coordinates of the point.

Solution:

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Answer:(a) Differentiate before substituting; (b) Gradient \(6\); (c) Point \((3,10)\).

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