The area of a growing circular patch is$$A=\pi(2+t)^2\text{ cm}^2.$$ Find: its average rate of incre

Question

The area of a growing circular patch is$$A=\pi(2+t)^2\text{ cm}^2.$$ Find: its average rate of increase between $t=0$ and $t=2$; its instantaneous rate of increase at $t=2$.

Accepted Answer

(a) Average rate $=6\pi\text{ cm}^2/\text{s}$; (b) Instantaneous rate $=8\pi\text{ cm}^2/\text{s}$.

Differentiation

Differentiation

Solution:

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