The quantities $x$ and $y$ satisfy $$y=\frac{12}{x},\qquad x0.$$ When $x=3$, $y$ is

Question

The quantities $x$ and $y$ satisfy $$y=\frac{12}{x},\qquad x>0.$$ When $x=3$, $y$ is increasing at $0.8$ units/s. Find $\dfrac{\mathrm{d}x}{\mathrm{d}t}$.

Accepted Answer

$\frac{\mathrm{d}x}{\mathrm{d}t}=-0.6$ units/s.

Differentiation

Differentiation