For $y=2\sqrt{x}+\frac3x-x^2, x0,$ find: the gradient function; the gradient at $x=1$.

Question

For $y=2\sqrt{x}+\frac3x-x^2, x>0,$ find: the gradient function; the gradient at $x=1$.

Accepted Answer

(a) $y'=\frac{1}{\sqrt{x}}-\frac{3}{x^2-2x}$; (b) Gradient $-4$.

Differentiation