For $$y=(x^2+1)(2x-3),$$ find $\frac{\mathrm{d}y}{\mathrm{d}x}$: using the product rule; by expand

Question

For $$y=(x^2+1)(2x-3),$$ find $\frac{\mathrm{d}y}{\mathrm{d}x}$: using the product rule; by expanding first. Show that the answers agree.

Accepted Answer

Both methods give $y'=6x^2-6x+2$.

Differentiation