The velocity of a car at time $t$ (in seconds) and at displacement $x$ (in m) is given by \(v =

Question

The velocity of a car at time $t$ (in seconds) and at displacement $x$ (in m) is given by $v = x + 4t$, for $0 \le t \le 3$. Given that $x = 0$ when $t = 0$, find: The displacement $x$ in terms of $t$ only The acceleration of the car at time $t = 2$ s

Accepted Answer

(a) $x=4e^t-4t-4\ \mathrm m$, $0\le t\le3$. (b) $4e^2\ \mathrm{m\,s^{-2}}\approx29.6\ \mathrm{m\,s^{-2}}$.

Differential Equations - Modelling with Differential Equations

Differential Equations - Modelling with Differential Equations

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