A first-order differential equation is separable when it can be rearranged so that all \(y\)-terms accompany \(\mathrm{d}y\) and all \(x\)-terms accompany \(\mathrm{d}x\).
Three common templates
| Original form | Separated integral | Restriction or check |
|---|---|---|
| \(\displaystyle\frac{\mathrm{d}y}{\mathrm{d}x}=p(x)q(y)\) | \(\displaystyle\int\frac{1}{q(y)}\,\mathrm{d}y=\int p(x)\,\mathrm{d}x\) | Check \(q(y)=0\) before dividing. |
| \(\displaystyle\frac{\mathrm{d}y}{\mathrm{d}x}=\frac{p(x)}{q(y)}\) | \(\displaystyle\int q(y)\,\mathrm{d}y=\int p(x)\,\mathrm{d}x\) | The original equation requires \(q(y)\ne0\). |
| \(\displaystyle\frac{\mathrm{d}y}{\mathrm{d}x}=\frac{q(y)}{p(x)}\) | \(\displaystyle\int\frac{1}{q(y)}\,\mathrm{d}y=\int\frac{1}{p(x)}\,\mathrm{d}x\) | Require \(p(x)\ne0\); check \(q(y)=0\). |
If \(q(y_*)=0\), then \(y=y_*\) may be a constant solution. Test it in the original differential equation before dividing by \(q(y)\).
Method
An implicit relation between \(x\) and \(y\) is acceptable unless the question requires \(y\) explicitly as a function of \(x\).
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