Give your answer in the form of \(y = \mathrm{f}(x)\).
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(a) \(2x\tan y+x^2\sec^2y\,\frac{\mathrm dy}{\mathrm dx}\).
(b) \(y=\tan^{-1}\left(\frac{x^4-1}{4x^2}\right)\), \(x>0\), on the branch through \((1,0)\).
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