<p>Find the equation of the tangent to the curve \(y = \mathrm{e}^{2x}\) at the point where&nbsp;\(x = 1\). Give your answer in terms of \(\mathrm{e}^2\).<span class="inline-marks">[6]</span></p>

Find the equation of the tangent to the curve \(y = \mathrm{e}^{2x}\) at the point where \(x = 1\). Give your answer in terms of \(\mathrm{e}^2\).

Derivatives of Exponential, Logarithmic and Trigonometric Functions

International Baccalaureate Mathematics: Applications and Interpretation Standard Level