The curve for which $\frac{\mathrm{d}y}{\mathrm{d}x} = \frac{a}{(1-2x)^2} + 3$, where $a$ is a c

Question

The curve for which $\frac{\mathrm{d}y}{\mathrm{d}x} = \frac{a}{(1-2x)^2} + 3$, where $a$ is a constant, is such that the tangent to the curve at $(1, -3)$ is perpendicular to the line $7y + x + 20 = 0$. Find the value of $a$. Explain whether this curve has a stationary point. Find the equation of the curve.

Accepted Answer

(a) $a=4$ (b) No stationary point (c) $y=\frac{2}{1-2x}+3x-4$

Differentiation - Tangents and Normals at a Point

Differentiation - Tangents and Normals at a Point

Video Solution:

Solution:

Solution locked