Techniques of Differentiation - Derivatives of Trigonometric Functions

Techniques of Differentiation - Derivatives of Trigonometric Functions

Differentiate \(x \cos 3x\) with respect to \(x\). Hence, show that \(\displaystyle\displaystyle \displaystyle\int_{0}^{\frac{\pi}{9}} x \sin 3x \, \mathrm{d}x = \frac{\sqrt{3}}{18} - \frac{\pi}{54}\).

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Answer:\(\frac{\mathrm d}{\mathrm dx}(x\cos 3x)=\cos 3x-3x\sin 3x\) Hence: \(\int_0^{\pi/9}x\sin 3x\,\mathrm dx=\frac{\sqrt3}{18}-\frac{\pi}{54}\)

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