Integration - Definite Integral
Evaluate the following
\(\displaystyle\displaystyle \displaystyle\int_{-2}^{3} 3x^3 - 2x \, \mathrm{d}x\)
\(\displaystyle\displaystyle \displaystyle\int_{1}^{3} \frac{3x^3 + 4x}{x^4} \, \mathrm{d}x\)
\(\displaystyle\displaystyle \displaystyle\int_{7}^{14} 3\sqrt{x + 2} \, \mathrm{d}x\)
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Answer:(a) \(\frac{175}{4}\) (b) \(3\ln3+\frac{16}{9}\) (c) \(74\)